Puzzles — BSSC General Intelligence And Reasoning

Explanation:

• There are 3 positions: 3 (Top), 2 (Middle), and 1 (Bottom).

• C is at the bottommost position, so C is at position 1.

• A is immediately above B, which means they occupy the only two consecutive spots left (positions 3 and 2 respectively).

• Therefore, Box A is at the top.

Exam Trick:

• Always fix the absolute positions first (C at the bottom). The remaining boxes automatically fall into place.

Explanation:

• Q lives on an even floor (2 or 4).

• Case 1: If Q is on floor 2, S is on 1. Then P and R must be on 4 and 3. But P cannot be on the topmost floor (4). So this case is invalid.

• Case 2: Q is on floor 4. S is immediately below Q, so S is on 3.

• P lives above R. So P is on 2 and R is on 1. (This satisfies the condition that P is not on floor 4).

• Therefore, R lives on Floor 1.

Exam Trick:

• Use options elimination based on negative constraints (P is not on top, immediately rule out combinations forcing P to the top).

Explanation:

• First, place the direct clue: Y gives the exam on Wednesday.

• W gives the exam immediately before Y. Therefore, W gives the exam on Tuesday.

• Z does not give the exam on Monday. The only remaining day for Z is Thursday.

• The remaining person, X, must give the exam on the remaining day, which is Monday.

Exam Trick:

• For day-based puzzles, map out the days in order (Mon, Tue, Wed, Thu) and fill direct clues first. Negative clues (Z not on Monday) easily fill the gaps.

Explanation:

• Let the positions be 5 (Top) to 1 (Bottom).

• Box X is at the bottom (Position 1).

• V is kept above Z with exactly two boxes between them. The available spaces are 5, 4, 3, 2. To have a gap of 2 boxes, V must be at 5 and Z must be at 2.

• The remaining boxes W and Y must fill positions 4 and 3. Since W is immediately above Y, W is at position 4 and Y is at position 3.

• Therefore, Box W is at the 2nd position from the top (Position 4).

Exam Trick:

• Anchoring 'X' at position 1 immediately limits V and Z's gap to positions 5 and 2. This leaves no alternate cases for W and Y.

Explanation:

• The available months are January, February, and March.

• Q's birthday is in March (Fixed condition).

• P's birthday is not in January. Since March is already taken by Q, P's birthday must be in February.

• Therefore, the remaining person R has a birthday in January.

Exam Trick:

• In puzzles with very few variables, mark the fixed variable first (Q = March), then immediately apply negative statements (P ≠ Jan) to the remaining slots.

Explanation:

• Draw 5 seats: 1, 2, 3, 4, 5.

• C is exactly in the middle: Seat 3.

• A sits to the immediate left of C: Seat 2.

• E sits at the extreme right end: Seat 5.

• D is not an immediate neighbor of E. Thus, D cannot sit at Seat 4. D must sit at Seat 1.

• The remaining person, B, sits at Seat 4.

• The final arrangement from left to right is: D, A, C, B, E.

Exam Trick:

• For middle and extreme end conditions, place them directly. The negative condition for D (not next to E) forces D to the extreme left without needing extra cases.

Explanation:

• A is taller than B: $A > B$

• A is shorter than C: $C > A$

• Combining these: $C > A > B$

• D is the shortest, so D comes at the very end: $C > A > B > D$

• Therefore, C is the tallest.

Exam Trick:

• If asked for the tallest, quickly eliminate anyone who is shorter than someone else. A is shorter than C (eliminate A). B is shorter than A (eliminate B). D is the shortest (eliminate D). C remains.

Explanation:

• M lives on floor 4.

• Two floors between M and Q. The only space available is floor 1. So, Q lives on floor 1.

• P lives immediately above N. They need two consecutive empty floors. The only consecutive empty floors are 3 and 2. So, P is on floor 3 and N is on floor 2.

• The remaining person R must occupy the remaining top floor 5.

Exam Trick:

• Directly placing M at 4 forces Q to 1 (because 4 + 3 goes out of bounds, so 4 - 3 = 1). This leaves exactly one pair of adjacent floors (3 and 2) for P and N, effortlessly leaving floor 5 for R.

Explanation:

• Let the positions be 4 (top) to 1 (bottom).

• S is not at the top (not 4). Q is immediately below S. So (S, Q) can occupy positions (3, 2) or (2, 1).

• Case 1: (S, Q) at (3, 2). The remaining positions 4 and 1 are for P and R. Since P is above R, P=4 and R=1. Here, P(4) and S(3) are adjacent. But the condition says P is NOT adjacent to S. So this case is invalid.

• Case 2: (S, Q) at (2, 1). The remaining positions 4 and 3 are for P and R. P above R means P=4 and R=3. P(4) and S(2) are not adjacent. This is valid.

• Final arrangement: 4-P, 3-R, 2-S, 1-Q.

• Therefore, Q is at the bottommost position.

Exam Trick:

• Instantly check combinations that violate adjacency rules. Placing S at 3 forces P to 4, violating the 'P not adjacent to S' rule. Hence, S must move down to 2.

Explanation:

• Mathematics is on Tuesday.

• A gap of two days between Mathematics (Tuesday) and History means skipping Wednesday and Thursday. So, History is on Friday.

• English is immediately after Science. The only two consecutive days left are Wednesday and Thursday. So, Science is on Wednesday and English is on Thursday.

• The remaining subject, Art, must be scheduled on the remaining day, Monday.

Exam Trick:

• For schedule puzzles, block the fixed entities first (Math = Tue). Count gaps carefully: a 'gap of two days' means two empty slots between the entities.